16a^2+16a-2=4

Solution for 16a^2+16a-2=4 equation:

16a^2+16a-2=4

We move all terms to the left:

16a^2+16a-2-(4)=0

We add all the numbers together, and all the variables

16a^2+16a-6=0

a = 16; b = 16; c = -6;
Δ = b2-4ac
Δ = 162-4·16·(-6)
Δ = 640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{640}=\sqrt{64*10}=\sqrt{64}*\sqrt{10}=8\sqrt{10}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-8\sqrt{10}}{2*16}=\frac{-16-8\sqrt{10}}{32}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+8\sqrt{10}}{2*16}=\frac{-16+8\sqrt{10}}{32}
$